T20 齐次解与特解的关系

• 知齐次解 ${\alpha }_1+2{\alpha }_2-{\alpha }_3=0\Rightarrow A\left(\begin{array}{c}1\\ 2\\ -1\end{array}\right)=0$
• 知非齐次特解 $A\left(\begin{array}{c}1\\ 1\\ 1\end{array}\right)=\beta$
• 故通解 $\alpha =k\left(\begin{array}{c}1\\ 2\\ -1\end{array}\right)+\beta$

(normal-distribution-absolute-value)=